6x-7x^(1/2)+1=0

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Solution for 6x-7x^(1/2)+1=0 equation: 


D( x )

x < 0

x < 0

x in <0:+oo)

6*x-(7*x^(1/2))+1 = 0

6*x-7*x^(1/2)+1 = 0

t_1 = x^(1/2)

6*t_1^2-7*t_1^1+1 = 0

6*t_1^2-7*t_1+1 = 0

DELTA = (-7)^2-(1*4*6)

DELTA = 25

DELTA > 0

t_1 = (25^(1/2)+7)/(2*6) or t_1 = (7-25^(1/2))/(2*6)

t_1 = 1 or t_1 = 1/6

t_1 = 1/6

x^(1/2)-1/6 = 0

1*x^(1/2) = 1/6 // : 1

x^(1/2) = 1/6

x^(1/2) = 1/6 // ^ 2

x = 1/36

t_1 = 1

x^(1/2)-1 = 0

1*x^(1/2) = 1 // : 1

x^(1/2) = 1

x^(1/2) = 1 // ^ 2

x = 1

x in { 1/36, 1 }

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